Question

mohon ate 1/4 of chaptti and distributed the remaining to two children equally .How much did each child eat?​

Answer 1

Answer:

• 3/8th part of chapatti ate both children.

Given :

• Mohan ate 1/4 of chaptti.

• Distributed the remaining to two children equally.

To find :

• How much did each child eat = ?

Step-by-step explanation:

Remaining chapatti = a chapatti - no. of chapatti which Mohan ate.

So, 1 - 1/4

= 4 - 1/4

= 3/4

Distributed remaining chapatti in two children equally,

= (3/4)/2

= 3/4 × 1/2

= 3/8.

So, 3/8th part of chapatti ate each child.

Answer 2

Step-by-step explanation:

Answer:-

$\sf\dfrac{3}{8}$

Given :-

Mohan ate 1/4 of chapatti and distributed the remaining to two children equally.

To find :-

The portion each child ate.

Solution :-

The whole part = 1

Portion Mohan ate =

$\sf\dfrac{1}{4}$

Left part = 1-$\sf\dfrac{1}{4}$

===> $\sf\dfrac{4}{4}$ - $\sf\dfrac{4}{4}$

===> $\sf\dfrac{3}{4}$

Given that,

Two children ate the remaining portion equally.

The remaining portion = $\sf\dfrac{3}{4}$

Two children ate = $\sf\dfrac{3}{4}$

Each child ate = $\sf\dfrac{3}{4}$ ÷ 2

Each child ate = 3/8.