Question

Moist heat sterilization of spores at 121 oC follows first order kinetics as per the
expression:
dN/dt=-kdN where, N is the number of viable spores, t is the time, kd is the rate constant
and dN/dt is the rate of change of viable spores. If kd value is 1.0 min-1, find the time
(in minutes) required to reduce the number of viable spores from an initial value of 1010
to a final value of 1 is (up to two decimal places).

Answer 1

Answer:

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Explanation:

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