Question

Moist oxygen was collected at 27 degree celsius and 740 mm pressure. The volume of the gas was found to be 40ml. Find the volume of the gas at 0 degree celsius and 760mm pressure. Given that aqueous tension=26.5 at 27 degree celsius.

Answer 1

p1v1/t = p2v2/t

740 * 40/0 =760 * 26.5/27

Answer 2

Volume of the gas at 0 degree celsius and 760mm pressure is 34 ml

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 740- 26.5 = 713.5 mm Hg

$P_2$ = final pressure of gas = 760 mm Hg

$V_1$ = initial volume of gas = 40 ml

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $27^oC=273+27=300K$

$T_2$ = final temperature of gas = $0^oC=273+0=273K$

Now put all the given values in the above equation, we get:

$\frac{713.5\times 40}{300}=\frac{760\times V_2}{273}$

$V_2=34ml$

Thus volume of the gas at 0 degree celsius and 760mm pressure is 34 ml

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