Math, asked by asimmazhari449, 1 year ago

Moiz is three times as old as his son. Their combined age is 48 years. What is their present age.

Answers

Answered by rithinv78
0

Answer:

36 and 12

Step-by-step explanation:

ratio of moiz: son =  3:1

sum of ages = 48

so 3+1 = 4 units= 48

1 unit = 48/4 = 12

so the preasent ages are 12*3 = 36 and 12*1 = 12

age of moiz = 36 and his son = 12

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Answered by Anonymous
0

Answer:

Age of Moiz son is x = 12 years

Age of Moiz is 3x = 3×12 = 36years

Step-by-step explanation:

Let the age of the son be x and age of Moiz be 3x.

According to statement:

3x+x = 48

=> 4x =48

=> x =48/4

=> x = 12

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