Question

Molality(m) of a sulphuric acid solution in which the mole
fraction of water is 0.85 is:​

Answer 1

Explanation:

mol fraction of water in solution = 0.85

So mol of acid = 1-0.85 = 0.15

Now

m= 100* mol of acid

_________________________

nw* molecular weight of water

m = 1000*0.15

__________

0.85* 18

= 9.8 mol/kg

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