Question

Molality of 100g of 20%(%)
of aqueous common
salt solution is approx:
1) 4.27m 2) 6.25m
3) 5.66m 4) 7.82 m​

Answer 1

Answer:

Mass = 100g

20%(w/w)

Molality = (mass / Molar mass)/ mass of solvent

Here mass of common salt = 20/100*100

hence,

mass of common salt = 20g

Total calculate molar mass,

molar mass of Common salt = 40g/mol

Substituting ,

Molality = (20/40)*1000/100

0.5*10

Molality =5m

Hope this will help uh