Chemistry, asked by faithyetty2678, 1 year ago

Molality of 2.5 g of ethanoic acid ch2cooh in 75 g of benzene

Answers

Answered by VIDYAgaikwad

1

Explanation:

2.5×10^-3÷60×10^-3×0.075

=2.5÷60×0.075

=2.5÷4.5

=0.56 molkg-1

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