Question

Molality of 23.0% by mass acetic acid solution

Answer 1

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Answer 2

Concept:

Molal concentration is another term for molality. It is a determination of a solution's solute concentration. Solute and solvent are the two elements that make up the solution.

Given:

Percentage by mass of acetic acid solution = 23.0 %

Find:

The molality of 23.0% by mass acetic acid solution is?

Solution:

The mass of solute and solution can be calculated as follows below:

Mass % = (Mass of solute / Mass of solution) * 100

(23/100) = (Mass of solute / Mass of solution) * 100

Thus, the mass of solute = 23 g

and the mass of solvent = 100 g

We know that mass of solutions can be written as:

Mass of solution = Mass of solute - Mass of the solvent

Mass of solvent = Mass of the solution - Mass of solute

Mass of solvent = 100 g - 23 g = 77 g = (77/1000) Kg = 0.077 Kg

The number of moles of solute can be calculated as:

The number of moles of substance = Mass of solute / Molar mass of the substance

The molar mass of acetic acid = 60 g/mol

By substituting the given values in the above expression, we can calculate the number of moles of the substance.

The number of moles of substance = 23 g / 60 g/mol = 0.384 mol

Now, the molality of a solution can be calculated as:

Molality = number of moles of solute / Weight of the solvent in kg

Molality = 0.384 mol / 0.077 Kg

Molality = 4.987 mol/Kg

Molality = 4.99 mol/Kg

Hence, the molality of 23.0% by mass acetic acid solution is 4.99 mol/Kg.

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