Question

Molality of a solution containing1.8 g of glucose dissolved in 250g of water is

Answer 1

Molality =  $\frac{No.\:\:of\:\:moles\:\:of\:\:solute}{Mass\:\:of\:\:solvent\:\:in\:\:Kg}$

Mass of solvent = 250/1000 = 0.25Kg

No. of moles of solute = 1.8/180 = 0.01

So, molality = 0.01/0.25 = 1/25 = 0.04 is your answer

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Answer 2

Answer:

the molality of a solution containing 1.8g of glucose dissolved in 250g of water