Molality of an aq. solution of urea having mole fraction 0.2 is
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According the given details, Molality of an aq. solution of urea having mole fraction is 0.2.
Hence, we need to calculate the molality (m)
M = XA x 1000)/ (XB x mol.wt. of B)
XB =1-XA
XB =the mole fraction of water
M = (XA x 1000)/ (1-XA) mol.wt. of B
XA = mole fraction of glucose
XA =0.02
1-XA =1–0.02 =0.98
m =2000/98 x 18
m=1.13 mole/kg
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