Question

Molality of an aqueous solution having 0.2 mole fraction of CH3COOH is

Answer 1

Answer:-

16.66 m

Explanation:-

Mole - 0.2

Moler mass of CH3COOH is 60.052

So mass of aqueous solution is

60.052

Mole x Moler mass

0.2 x 60.052

= 12.01 g

= 0.012 kg

Now, molality of aqueous solution is,

mole % kilogram

0.2 % 0.012

= 16.66 m

So molality of an aqueous solution having 0.2 mole fraction of CH3COOH is 16.66 m.

You find molality from using given equation:

molality = mole / mass

Here mass in Kilogram.