molality of pure liquid benzene if its density is 1.2 g/ml
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Explanation:
Given,
Density=1.2gm/ml
From this we can say that 1.2 gm of benzene 1 ml solution..
But as we had a pure liquid benzene Mass of solute
=mass of solvent
=1.2 gm We know that Molality
=mole of solute /mass of solvent in kg. Mole of benzene = 1.2/78;
Mass of solvent =1.2 gm =1.2/1000 kg Thus, Molality =(1.2/78)×(1000/1.2) =12.8 m Molality =(1.2/78)×(1000/1.2) =12.8 m.
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