Molality of pure liquid Ethanol (C2H5OH) if its density is 1.2gm/mL?
Answers
Answered by
1
Answer: 21.43
Explanation:
Here it is given that ethanol is pure so
Solvent= solute
1.2g = 1.2g
m= no.of moles of solute ÷ mass of solution in kg
1.2g÷46/1.2÷1000
= 21.73(approx)
Attachments:
Similar questions