molality of pure water ???
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Answered by
2
At room temperature it's 55.55 M.
We can derive it in the following way,
Density = mass / volume = 1000kg/m^3
volume = (mass/1000) m^3
Let the no. of moles there be x,
Now,
volume = (18x / 1000)m^3.
since mass = (no. of moles × molar mass),
Molarity =( x/ (18x/1000)) M = (1000/18) M = 55.55 M
We can derive it in the following way,
Density = mass / volume = 1000kg/m^3
volume = (mass/1000) m^3
Let the no. of moles there be x,
Now,
volume = (18x / 1000)m^3.
since mass = (no. of moles × molar mass),
Molarity =( x/ (18x/1000)) M = (1000/18) M = 55.55 M
Answered by
4
The molality of pure water:
Molality is a measure of the concentration of a solute in a solution in relation to the amount of substance in a definite amount of mass of the solvent.
The molality of pure water:
The density of water= 1g/ml
The molar mass of water=18
Moles of water in 1000g or 1kg= 1000/18=55.5
So, the molality is equal to 55.55.
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