Question

Molar conductance of ca and cl are given. Equivalent conductance

Answer 1

Explanation:

equivalent conductance formula ÷ 1000K/N

here N= normality

according to question , you have the Molarity of Ca and CL

now we need N

so N= molarity × nth factor of CaCl2

once you get Normality , then you get the equivalent conductance

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