Question

Molar conductivity of a solution 1.26 x 10² ohm^(-1) cm^(2) mol^(-1).
Its molarity is 0.01. Its specific conductivity will be
(A) 1.26 x 10^(-25)
(B) 1.26 x 10^(-3)
(C) 1.26 x 10^(-4) (D) 0.0063​

Answer 1

Answer:

B option is correct

(B)1.26×10^(-3)