Question

. Molar heat of vaporisation of a liquid is 6kJ mol-1. If
the entropy change is 16J mol-'K-?, the boiling point
of the liquid is..​

Answer 1

Explanation:

del S vap = del H vap/ b.p

b.p = del H vap/del S vap

= 6/16= 3/8= 0.37 K