Question

Molar volume is the volume occupied by 1 mole for any ideal gas at STP. Show that it is 22.4 L. Given R = 8.31 Joule / mole K

Answer 1

Answer :

$n=1$

$T=273K$

$P=1\:atm=1.01\times 10^{5}\:N/m^2$

$R=8.31\:J/mol\:K$

$V=?$

For 1 mole,

⇒ $PV=RT$

⇒ $V=\frac{RT}{P}$

⇒ $V=\frac{8.31\times 273}{1.01\times 10^5}$ $m^3$

⇒ $V=\frac{8.31\times 273\times 10^3}{1.01\times 10^{5}}$ L

⇒ $V=22.4$ L

Answer 2

ANSWER

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