Question

Molar volume is the volume occupied by 1 mole of any (ideal) gas at standard temperature and pressure (STP: 1 atmospheric pressure, 0 °C). Show that it is 22.4 litres.

Answer 1

this is based on avogadro principle.
all gases contains equal volume at equal temperature and pressure .
PV=nRT
(V/n)=RT/P=molar volume
now
molar volume=RT/P
put p=1 atm =1.013 x10^5 N/m^2
R=8.31 jk-1mole-1
T=273K

molar volume=8.31 x 273/(1.013 x 10^5) m^3
=2239.51 x 10^-5m^3
=2239.51 x 10^-2 litres
=22.3951 litres=22.4litres (approx)

Answer 2

here n=1mole
T=273K
R=8.31J/mole/K
P=1atm. 0.76mm of hg
0.76×9.8×13.6×10^3N/m^2
using relation:
PV=nRT
V=nRT/P
1×8.31×273/0.76×9.8×(13.6×10^3)
22.4×10^- 3m^3
22.4litres