Chemistry, asked by hammad3353, 10 months ago

Molarity of 0.5 N sulphuric acid solution is

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Answered by sreeh123flyback
0

normality=molarity×molar mass/equvivalent mass

FOR ACIDS

normality=molarity×basicity

basicity=number of H+ ions in the ACID

0.5=molarity×2

H2SO4=(baicity)=2

malarity=0.5÷2=0.25M

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