Question

Molarity of 1g H2SO4 solution in 1litre

Answer 1

Answer:

no of moles of sulfuric acid in 1gm is

1/98 moles..........(i)

volume of solution in litre is

1 ltr..........( ii)

since, Molarity is ratio of number of moles of solute by volume of solution in litre

hence (I) : ( ii) is 1/98M

Answer 2

Answer:

$\blue\displaystyle{Molarity=0.010 \ M}$

Explanation;

$\displaystyle{Given \ mass \ is \ 1 \ g}\\\\\\\displaystyle{Molar \ mass \ of \ H_2SO_4=2+32+64=98 \ g}\\\\\\\displaystyle{No. \ of \ moles=\dfrac{Given \ mass}{Molar \ mass}}\\\\\\\displaystyle{No. \ of \ moles=\dfrac{1}{98}}\\\\\\\displaystyle{No. \ of \ moles=0.010 \ moles}$

$\displaystyle{Molarity=\dfrac{No. \ of \ moles \ of \ solute}{volume \ of \ solution(L)}}\\\\\\\displaystyle{Putting \ value \ here }\\\\\\\displaystyle{Molarity=\dfrac{0.010}{1}}\\\\\\\displaystyle{Molarity=0.010 \ M}\\\\\\\displaystyle{Molarity=0.010 \ M}$

Thus we get Molarity of solution is 0.010 Molar .