Molarity of 1m aqoues NaOH density of the solution is1.02gr/ml
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ok dude . so what we are asked to find?
Answered by
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Explanation:
(here i am beleiving that by writing 1m,you mean 1 molal)
relation between molality and molarity:
molality(m)=1000*M/(1000*d-W2),
where,
M is moarity
d is density of solution in g/ml
W2 is the weight of the given solute(here naoh)
so the equation becomes 1=1000*M/(1000*1.02-40)
so it becomes M=980/1000=0.98M
hope this help you
thank you
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