Question

Molarity of 1m aqueous NaOH solution [density of the solution is 1.02 g|m|]

Answer 1

Answer:

0.98

Explanation:

The relationship between molarity and molality is given by:

M =1000 × d/(1000/m) + M'

where M= Molarity

m = Molality => 1

d = density

M' = Molecular weight of solute => 23+16+1 = 40

Substituting our values

M = 1000 × 1.02 / (1000/1) + 40

= 1020 / 1040

= 0.98