Question

Molarity of 20% of h2so4 by mass whose density is 1.02 g/cm3 is ?? 1)8.4M 2) 2.08M 3)7.28M 4) 1.7M *(EXPLAIN IN DETAIL I BEG EVERYONE I AM A LEARNER)*

Answer 1

Given :

• % m / m = 20%
• density of solution = 1.02 g / cm³
• molar mass of H2SO4 = 98 g

To find :

• Molarity

Solution :

•20% mass / mass means 20 gram of solute in 100 g solution

200 g solute will be present in 1000 g solution

For H2SO4:

mass of solute = 200 g

molar mass of solute = 98 g

we know that ,

$\bigstar\boxed{ \mathtt{ \large{moles = \frac{mass}{molar \: mas} }}}$

$\rightarrow \mathtt {\large{moles = \frac{200}{98} }}$

$\rightarrow \mathtt {\large \red{moles = 2.04}}$

For solution :

density of solution = 1.02 g / cm³

mass of solution = 1000 g

we know that ,

$\bigstar\boxed{ \mathtt{ \large{volume = \frac{mass}{density} }}}$

$\rightarrow \mathtt {\large{volume = \frac{1000}{1.02} }}$

$\rightarrow \mathtt{ \blue {\large{volume = 980 \: ml}}}$

moles of H2SO4 = 0.2

volume of solution = 980 ml = 0.98 L

we know that ,

$\bigstar\boxed{ \mathtt{ \large{molarity = \frac{moles \: of \: solute}{vol \: of \: soln} }}}$

$\rightarrow \mathtt {\large{molarity = \frac{2.04}{0.98} }}$

$\rightarrow \mathtt{ \green {\large{molarity = 2.08M}}}$

Answer 2

Given :

% m / m = 20%

density of solution = 1.02 g / cm³

molar mass of H2SO4 = 98 g

To find :

Molarity

Solution :

•20% mass / mass means 20 gram of solute in 100 g solution

200 g solute will be present in 1000 g solution

For H2SO4:

mass of solute = 200 g

molar mass of solute = 98 g

we know that ,

$★ volume= \frac{mass}{density}$

$\rightarrow \mathtt {\large{volume = \frac{1000}{1.02} }}$

$\rightarrow \mathtt{ \blue {\large{volume = 980 \: ml}}}$

moles of H2SO4 = 0.2

volume of solution = 980 ml = 0.98 L

we know that ,

★ $molarity= \frac{moles\:of\:solute}{vol\:of\:soln}$

$\rightarrow \mathtt {\large{molarity = \frac{2.04}{0.98} }}</p><p>$

$\rightarrow \mathtt{ \green {\large{molarity = 2.08M}}}$

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HOPE IT HELPS!!