Question

Molarity of 4.9% (w/v) h2so4 having density 1.4
g/ml?

Answer 1

Explanation:

4.9 % acid by mass means 4.9g acid in 100 g solution.

Density = 1.02 g/mL

Volume of  solution = Mass /density

= 100/1.02

= 98.03 ml

Molar mass sulphuric acid H₂So₄ = 2*1 + 32 + 4*16 = 98g/mol

Number of moles of sulphuric acid = mass /  molar mass

=4.9 / 98

=0.05

Molarity = number of moles / volume of solution in litres

= 0.05 / 0.9803

= 0.051 M

Normality = Molarity * Basicity

= 0.051*2 =0.102 N

Hence, the normality of 4.9% of H₂So₄ of density 1.02g/ml is 0.102N....

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