Molarity of a sodium chloride solute by dissolving 4 g of it in 250 ml of water is
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0
Answer:
Explanation:
Volume of the solution is V=250 ml=0.25 L. V = 250 m l = 0.25 L .
Answered by
0
Answer:
0.2735 M
Explanation:
Molar mass of NaCl = 23+35.5 = 58.5g
Mole of NaCl = Given mass ÷ molar mass
= 4 ÷ 58.5
Molarity (M) = Mole of solute ÷ Volume of Solution in litres
= (4 ÷ 58.5) ÷ 0.25 ('.' 250 ml = 0.25L)
= 0.2735 M
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