Question

molarity of a solution containing 30g of urea in 500mL of solution is​

Answer 1

Answer:

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Explanation:

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Answer 2

Molarity of a solution containing 30g of urea in 500mL of solution is 1 M

Molarity is the number of moles of solutes present one litre of solution

Explanation:

Molar mass of urea =60

given mass =30gm of urea

Molarity = number of moles of solvent ÷mass of the solvent (in litre)

Number of moles of solvent =mass ÷ molecular mass

Number of moles of solvent=30/60

Number of moles of solvent=0.5 moles

mass of the solvent (in litre)=500ml/1000ml

mass of the solvent =0.5 litre

Molarity = number of moles of solvent ÷mass of the solvent (in litre)

Molarity =0.5 moles ÷ 0.5 litre

Molarity = 1 molar or 1M

Molarity of a solution containing 30g of urea in 500mL of solution is 1 M