Question

molarity of a solution of H2SO4 is which 1.8g of H2SO4 is dissolved in 2 litre of water is?

Answer 1

Question :–

▪︎ Find molarity of a solution of ${ \bold{ H_{2} S O_{4} }}$ is which 1.8g of ${ \bold{ H_{2} S O_{4} }}$ is dissolved in 2 litre of water is ?

ANSWER :–

$\\ \to { \boxed{ \bold{ Molarity= 0.0091 \: M }}}$

EXPLANATION :–

GIVEN :–

• Mass of ${ \bold{ H_{2} S O_{4} }}$ = 1.8g

• Volume of ${ \bold{ H_{2} O }}$ = 2 L

TO FIND :–

• Molarity of Solution = ?

SOLUTION :–

$\\ { \bold{ \to \: Mass \: \: of \: \: { H_{2} S O_{4}} = 1.8g }}$

$\\ { \bold{ \to \: Number \: \: of \: \: moles \: \: of \: \: { H_{2} S O_{4}} = \dfrac{1.8}{98} }}$

$\\ { \bold{ \to \: Number \: \: of \: \: moles \: \: of \: \: { H_{2} S O_{4}} = \dfrac{0.9}{49} \: mol }}$

MOLARITY :–

Number of mole of solute per litre of solution is called MOLARITY .

$\\ \implies { \boxed{ \bold{ Molarity= \dfrac{number \: \: of \: \: mols}{volume \: \: of \: \: solution} }}}$

• Now put the values –

$\\ \implies { \bold{ Molarity= \dfrac{ \frac{0.9}{49} }{2} }}$

$\\ \implies { \boxed{ \bold{ Molarity= 0.0091 \: M }}}$