Question

molarity of a solution prepared by dissolving 75.5 gram of pure k o h in 540 ml solution is​

Answer 1

Answer:

molarity=given massx1000/molar massxvolume of solution

molarity= 75.5*1000/56x540

=2.5

Explanation:

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Answer 2

Answer:

2.5M of KOH is formed in 540ml of solution.

Calculation:

We are given the following data-

1. The mass of $KOH$- 75.5g
2. The volume of the solution- 540ml=0.54L

First, we convert the mass to moles by using the mole formula.

$Moles=\frac{Mass}{Molar Mass}$

The molar mass of $KOH$ is 56g/mol.

$Moles = \frac{75.5}{56}$

$Moles=1.35 mol$ of $KOH$

Second, we convert the moles to molarity using the molarity formula.

$Molarity= \frac{Moles}{Volume}$

$Molarity=\frac{1.35}{0.54}$

$Molarity= 2.5 M$ of $KOH$