Question

Molarity of a solution which is prepared by mixing 0.2 mol sugar in 500 ml water is

Answer 1

Answer:

Molarity = (mass/molar mass) × 1000/volume[in ml]

Molarity = moles/volume[in L]

Molarity = 0.2/0.5 = 0.4

So the molarity of solution is 0.4M

Answer 2

Molarity of a solution which is prepared by mixing 0.2 mol sugar in 500 ml water is 0.4 M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute  = 0.2

$V_s$ = volume of solution in ml = 500 ml

$moles of solute =\frac{\text {given mass}}{\text {molar mass}}=0.2moles$

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{0.2moles\times 1000}{500ml}=0.4mole/L$

Therefore, the molarity of solution will be 0.4 M.

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