Molarity of aqueous solution of NaOH solution is 4 M and density of solution is 1.2 gm/mL, the
Molality of solutions will be
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Answer: 3.84
Explanation:
Assume that u have 1 lt. of solution..
Multiply 1 lt. with density (1.2g/ml) × 1000ml/L
This gives 1200 gm of solution..
4 M means 4 moles of NaOH per 1 lt. of solution
Now, Convert 4 moles to grams...
Molar mass of NaOH = 23+16+1 = 40
4 moles × 40 amu = 160 gm of NaOH..
1200 gm of solution - 160 gm of solute = 1040 gm of solvent..
Molality = 4 moles of solute ÷ 1.040 of solvent
m = 3.84 molal NaOH..
I hope u understood..
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