Question

Molarity of aqueous solution of NaOH solution is 4 M and density of solution is 1.2 gm/mL, the
Molality of solutions will be

Answer 1

Answer:

40g of NaOH is present in 100g of solution

Moles of NaOH = 40/40 = 1 mol

Volume of solution = Mass / Density

= 100 / 1.2

= 83.3 L

Molarity = moles of NaOH / Volume of solution

= 1 / 83.3

= 0.012 M

Molality = (Moles of NaOH / Wieght of solvent in grams) * 1000

= (1 / 90) * 1000

= 11.1 m

Answer