Molarity of aqueous solution of NaOH solution is 4 M and density of solution is 1.2 gm/mL, the
Molality of solutions will be
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40g of NaOH is present in 100g of solution
Moles of NaOH = 40/40 = 1 mol
Volume of solution = Mass / Density
= 100 / 1.2
= 83.3 L
Molarity = moles of NaOH / Volume of solution
= 1 / 83.3
= 0.012 M
Molality = (Moles of NaOH / Wieght of solvent in grams) * 1000
= (1 / 90) * 1000
= 11.1 m
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