Question

molarity of ch3cooh solution is 2M and density is 2g/ml then find the molality, mole fraction of the solution
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Answer 1

Explanation:

Suppose the volume of solution is 1000 ml

1 ml=1.2 gm

1000 ml=1020 gm

Number ofr moles =2⋅05M×1 lit=2.05 mol

Mass of solute =n×M⋅wt=2.05×60=123 gm

Solvent mass =1020−123=897 gm

Molality =60123×8971000=2.28 mol kg−1