Question

Molarity of H2SO4(density 1.8g/ml) is 18m.The molality of this H2SO4 is

Answer 1

Explanation:

answer is very simple

we have given molarity of H3PO3 =0.3M

so we can easily find out normality by knowing molarity

Normality=molarity*valency factor

N=0.3*2=0.6 which is answer

{in case of oxy acid of phosphorus valency factor is simple number of oxygen -1}

so in case of H3PO3 valency factor =3-1=2

thank you

Answer 2

Answer:

Explanation:see the pic