Question

molarity of H2SO4 is 18 M.the molarity of this solution is

Answer 1

first of all, let me finish the question of yours 

"Molarity of H2SO4 solution is 18M. If the density of the solution is 1.8g/ cm3. Calculate the molality of the solution"

If this right then follow the answer written below!

Molality = Number of moles (solute) / Volume of solvent (kg)

Density of solution = 1.8g/cm3
Water volume = 1.8g x 1000cm3 = 1800g        (1000cm3 = 1000g)

Molecular Weight Of H2SO4 = 2x(2)+(32)+4x(16)
                                                 = 98g

Volume Of H2S04 = 18(moles) x 98g = 1764g

Volume Of Solution = Volume Solvent + volume Solute
Volume Solvent = 1800g - 1764g
=36g or 0.0036KG

Molality = 18 H2S04 moles / 0.0036 kg
Molality = 18 / 36 x 10^-3
Molality = 0.5 x 10^3 mol / kg

Molality = 500 mol / kg

Hope this helps!

Answer 2

molarity=no of moles

so 18 moles are present

mass= no of moles multiply into molar mass of h2so4

18 *98=1764

molarity=no of moles of solute/mass of solvent

mass of solvent=?

d=1.8

d=m/v

volume=1000

mass= d*v

1.8*1000=1800

so mass of solution =1800

mass of solvent=1800-1764=36

molarity= no of moles of solute/mass of solvent

18/36*1000=0.5*1000=500

thanks to the previous question given by someone by which I got the correct question