Molarity of NaOH in a solution is 3. find normality
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The molarity of a sodium hydroxide solution can be determined by dividing the amount of sodium hydroxide (in moles) present by the number of liters of the overall solution. >> For example, if there are 50 moles of NaOH in 500 liters of solution, it is a 0.1 There is only 1 OH-, so the number of equivalents is 1. Look at a periodic table and find the sum of the atomic masses of the Na, O and H in your formula:
Na = 22.99; O = 16.00; H = 1.01. To sum, 22.99 + 16.00 + 1.01 = 40.00 g/mole
Eq = 40.00 / 1 = 40.00 g/eq
The gram equivalent weight of NaOH is 40.00 g/eq.molar NaOH solution.
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