Question

molarity of pure 1 lit sol of 98% w/v
h2so4 having density 1.88 g per ml​

Answer 1

Molar mass of H2SO4 = 98g/mol = Mm

D =density = 1.84g/cc

W/w = 98%

V = 1dm3 = 1L = 1000ml = 1000cc

Mass of solution = V x D

M = 1000 x 1.84 = 1840g per 1000cc

Using w/w, 98% of 1840g = H2SO4

= (98/100) x 1840 = 1803.2g = m

Nos of moles = m/Mm = 1803.2/98 = 18.4moles per 1000cc

Thus, molarity = 18.4M (18.4mol/dm3)