Question

Molarity of pure water,
assuming density of water
to be lg cm^-
3 is
i 1000 m
Im
18
is
m
1000​

Answer 1

molarity of pure water is -

$\frac{1000}{18} = 55.5$

Answer 2

Answer: 55.56 M

Explanation:

Molarity is defined as the number of moles of the solute per litre of solution.

Molarity=

Volume of solution in litre

No of moles of solute

We are given that the density of water is 1g/ml. This is equal to $$ 1 Kg/ L $$.

Therefore, the mass of 1L of water will be:

= Density of water × Volume

=1

L

Kg

×1L

=1Kg

=1000g

Therefore, number of moles in 1Kg of water =

molarmass

mass

=

18

1000

=55.56

Therefore, molarity of water = =

1L

55.56moles