Question

molarity of solution prepared by dissolving 2.6 into 10 to the power minus 2 mole of solute in 250 ml of solution​

Answer 1

Answer:

For starters, convert the mass of potassium bromide to moles by using the molar mass of the compound.

15.6

g

⋅

1 mole KBr

119.002

g

=

0.1311 moles KBr

Now, in order to find the molarity of the solution, you need to figure out how many moles of solute are present for every  

1 L

of solution.

You already know that  

1.25 L

of solution contain  

0.1311

moles of potassium bromide, the solute, so all you have to do now is to use this known composition as a conversion factor to go from  

1 L

of solution to number of moles of solute.

1

L solution

⋅

0.1311 moles

1.25

L solution

=

0.10488 moles KBr

Since this represents the number of moles of solute present in  

1 L

of solution, you can say that the molarity of the solution is equal to

molarity = 0.105 mol L

−

1

−−−−−−−−−−−−−−−−−−−−−−  

The answer must be rounded to three sig figs, the number of sig figs you have for your values.

Explanation:

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