Question

Mole fraction of 10%urea by mass of solution when dissolved in aqueos solution

Answer 1

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molar mass of urea = 60g

given mass of urea = 10 g

(here 10% by mass means 10 g of solute is dissolved in 100 g of solution)

so, n2 (no. of moles of solute) = 10/60 =0.16

n1 ( no. of moles of solvent ) = 90/18 = 5

X2 (mole fraction of solute) = n2/n1 + n2

=> 0.16 / 5.16 = 0.03 ans

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