Mole fraction of a solute in benzene is 0.2 then find the molality of solute
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Answer:
0.2=2/10;
na=2;nb=8;w=8×18=144
m=2/144=1/72
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- Mole fraction of solute = 0.2
Let molarity of solution = x
Moles of solute in 1000 g benzene
1000/78
12.82
Mole fraction of solute = x / x + 12.82
0.2 (x + 12.82) = x
0.2x + 2.564 = x
2.564 = x - 0.2x
x = 2.564/0.8
x = 3.2
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