Question

Mole Fraction of C3H5(OH)3 in a solution of 36g of water and 46g of glycerine is :
A) 0.46
B) 0.36
C) 0.20
D) 0.40

Answer 1

no. of moles of glycerine=46/92 (where 92 is M.M. of glycerine)
                                       =0.5moles
no. of moles of water=36/18(where 18 is M.M. of water)
                                 =2moles
so mole fraction oh glycerine=$\frac{no. of moles of glycerine}{no. of moles of glycerine+no. of moles of water}$
                                              =$\frac{0.5}{2+0.5}$
                                              =0.20

Answer 2

Answer:

0.20

Explanation:

36gm of H2O,46gm of glycerin

no of moles of glycerin =46/92=0.5moles

no of moles of water =36/18=2moles

mole fraction of glycerin =moles of glycerin /moles of water +moles  of                                                                                            

                                            glycerin    

                                         =0.5/2+0.5

                                         =0.2

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