Question

mole fraction of ethanol in an aqueous solution is 0.1. Then find its molality.​


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Answer 1

Answer:

Xa = 0.1

Xb = 1 - Xa

Xb = 1 - 0.1 = 0.9

GMW of H20 = 18

m = Xa * 1000/Xb * GMW

m = 0.1 *1000/ 0.9 * 18

= 100 / 16.2

=6.17 (Ans)

Ans:- The mole fraction of ethanol in an aqueous solution is 0.1. Then its molality is 6.17

Explanation:

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Answer 2

The mole fraction of ethanol in an aqueous solution is 0.1. Then its molality is 6.17M

Explanation:

• Molar concentration is a "measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of amount of substance per unit volume of solution".

mole fraction of ethanol in an aqueous solution $Xa = 0.1$

We know that $Xb = 1 - Xa$

substituting the value of mole fraction of ethanol.

$Xb = 1 - 0.1 = 0.9$

• Gram Molecular weight of H20 GMW = 18

• Molarity of the solution will be $m = Xa * 1000/Xb * GMW$

substituting the value in the above equation

$m = 0.1 *1000/ 0.9 * 18$

$m= 100 / 16.2$

$m=6.17$

The mole fraction of ethanol in an aqueous solution is 0.1. Then its molality is 6.17M