Question

Mole fraction of ethanol in its 4.45 molal aqueous
solution is
(1) 0.02
(2) 0.25
(3) 0.074
(4) 0.045

Answer 1

Answer:

Molality =no of moles of solute/mass of solvent (in kg) .here Molality =4.5 So, it means 4.5 moles of solute present in 1kg solvent.

Mole of solvent=1000/18=55.5

So Mole fraction of solute=4.5/4.5+ 55.5=4.5/60=3/40=""0.075.""

Explanation:

Answer 2

Mole fraction of ethanol in its 4.45 molal aqueous solution is 0.074

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molarity=\frac{n\times 1000}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent in g

Given : 4.45 molal aqueous solution, i.e. 4.45 moles of ethanol in 1 kg or 1000 g of water

Moles of ethanol = 4.45

moles of water =$\frac{\text {given mass}}{\text {Molar mass}}=\frac{1000g}{18g/mol}=55.6moles$

${\text {mole fraction of ethanol}=\frac{\text {moles of ethanol}}{\text {moles of ethanol+moles of water}}=\frac{4.45}{4.45+55.6}=0.074$

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