Question

Mole fraction of glycerine(C2H (OH),) in a solution
of 36 g of water and 46 g of glycerine is :
(1) 0.46
(2) 0.36
13) 0.20
(4) 0.40
a​

Answer 1

Answer:

0.8

Explanation:

Given:

Mass of water = 36gm

Mass of glycerine = 46 gm

Molar mass of water= 18

Molar  mass of glycerine= 92

No. of moles of  water= 36/18

                                    =2 moles

No. of moles of glycerine =46/92

                                           =0.5 moles

total moles =2 + 0.5                  

                  =2.5

Mole fraction of glycerine =no.of moles of glycerin / total no.of moles

                                           =0.5/2.5

                                            =0.2 moles

Mole fraction of  water=2/2.5

                                      =0.8

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