Question

Mole fraction of glycerine C3H5(OH)3 in solution containing 36 g of water and 46 g of glycerine is * 1

Answer 1

Answer:

0.2

Explanation:

Molar mass of glycerine = 92 g

No of moles of glycerine in the solution = 46/92 = 0.5

No of moles of water = 36/18 = 2

Mole fraction (X) = 0.5/(2+0.5) = 0.5/2.5 = 1/5 = 0.2