Mole fraction of H2 in a 2g mixture of H2 and He is 0.5. Thus He present in the mixture Is
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1gm or 0.25 mole of he
Explanation:
by law of conservation of mass,
mass of reactants is equal to mass of products.
1 mole of H2 = 2 gm
or, 0.5 mole of H2 =1gm
therefore He has to be 1 gm
4 gm of He =1mole
or, 1 gm of He = 0.25 mole
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