Question

Mole fraction of i2 in c6h6 is 0.2.calculate molality of i2 in c6h6

Answer 1

Answer:

Explanation:

No of moles in c6h6 in 1000g= 1000/78= 12.82. mole fraction of i2 in c6h6 = no of mole of I2/ no of moles of I2 + no of moles of c6h6. 0.2= x/ x+ 12.82. 0.2x + 2.564 = x. 2.564 = x- 0.2x. 2.564 = 0.8x. X= 2.564/0.8 = 3.2. Molality of i2 in c6h6 is 3.2

Answer 2

Answer:

3.2

Explanation:

Suppose, we have ten moles of the given solution.

Therefore we have 2 moles of iodine dissolved in 8 moles of benzene.

Molecular mass of benzene=78.

Molality= No. moles of iodine/Mass of solvent in kg  

Therefore 8 moles of benzene weighs  78∗8=624 g

Molality =(2∗1000)/624  

= 3.205