Question

Mole fraction of iodine in benzene is 0.2. Calculate molality of the solution.​

Answer 1

Answer:

The molality of the solution is 3.025(m)

Explanation:

let number of mole of iodine present is x and number of mole of benzene present it is y.

Then x÷(x+y) = 0.2

simplifying these we get 4x=y

Now molar mass of benzene is 78g.

Now molality= 1000x/78y=1000/(4×78)

=3.205(m)

If you are feeling any problem then you should revise the basic formulae.

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Answer 2

Answer:

3.025

Explanation:

Hope it will help you