Mole fraction of NaOH in 5 molal aqueous solution of NaOH is
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1 mol NaOH =40g
thus
5 mol NaOH =40×5 = 200g
water present = 1000-200=800 g
mole of water =800/18=44.5
mole fraction of NaOH=5/5+44.5
ans =0.101
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